X^2-30x+161=0

Solution for X^2-30x+161=0 equation:

X^2-30X+161=0

a = 1; b = -30; c = +161;
Δ = b2-4ac
Δ = -302-4·1·161
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-16}{2*1}=\frac{14}{2}
=7
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+16}{2*1}=\frac{46}{2}
=23
$